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数组遍

int[] is = new int[1,12,4,546] for(int i=0; i

public static void main(String[] args){ String[] arr = {"a","b","c"}; for(int i = 0; i < arr.length; i++){ System.out.print(arr[i] + " "); } //或者 System.out.println(java.util.Arrays.sort(arr));}

for (int i=0;i

@echo offset/p "input=Directory: "for /f "delims=" %%a in ("%input%") do ( echo "%%~na")pause>nul

$data = array(......); //原数组 $new_array = array(); //定义新数组; $key_array = array('title','describe'); //定义新数组需要的key foreach($data as $k=>$v){ $temp = array(); //定义临时数组 foreach($v as $kk=>$vv){ if(in_array($k...

如果重复怎么处理?是否需要做区分? 如果忽略重复和反向还原,那么直接用array_merge即可 $new_arr = array_merge($arr['1'],$arr[2]); foreach: foreach($arr as $v=>$k){ foreach($v as $val=>$key){ $new_arr[$key] = $val; }}

var arrays1 = ['1','2','3','4','5'],arrays2 = ['a','b','c','d','e'],arrays3 = ['v','w','x','y','z'];var arrays = [];var index = 0;while(true) { if (!arrays1[index] && !arrays2[index] && !arrays3[index]) break; var step = arrays...

数组是引用类型,int arr2[][]=arr1赋值了,arr1和arr2会指向同一块内存,2个引用操作同一块内存,arr2改变,自然arr1就变,当int arr2[][]= new int[3][3];开辟一块新的内存,2个内存不相互干扰,就不会有问题

$b=array();//空数组foreach ($arr as $a){ $b[]=$a['100864'];//添加值}print_r($b);

这个不好说,有横向遍历和纵向遍历,看你的需要,横向遍历要用到栈的知识,纵向就用递归就行(把数组给一个函数,函数判断数组里面的值,是不是数组,是数组就继续给自己这个数组,不是的话就输出到目标数组)

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